單片機計分器Proteus仿真程序兩個按鍵，每按下一次對應的計分器加1

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ID:263377 發表于 2021-2-1 17:21 | 只看該作者 |只看大圖回帖獎勵

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兩個按鍵，每按下一次對應的計分器加1

單片機源程序如下:
#include<reg51.h>
#define uint unsigned int
#define uchar unsigned char
#define dat P0
code uchar d[]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90};
uint second=0,minter=0,hour=0;
uint mge,mshi,hshi,hge;
static char court=0;
         sbit q1=P2^0;
                     sbit q2=P2^1;
                     sbit q3=P2^2;
                     sbit q4=P2^3;
                     sbit q5=P2^4;
                     sbit q6=P2^5;
                     sbit q7=P2^6;
                     sbit q8=P2^7;
                     sbit key1=P3^2;
                     sbit key2=P3^3;
void delay(uint number)
{
   uchar i,j;
      for(i=0;i<number;i++)
         for(j=0;j<200;j++);
}
void int11() interrupt 1 using 2
{
TH0=0x5c;
TL0=0xb0;
//court++;
}

void int0() interrupt 0 using 1       minter++;
  if(minter==99)
minter=0;
}
void int1() interrupt 2 using 1
{
hour++;
if(hour==99)
hour=0;
}
void main()
{
TMOD=0X01;
TH0=0x5c;
TL0=0xb0;
ET0=1;
EX0=1;
EX1=1;
IT0=1;
IT1=1;
EA=1;
TR0=1;
while(1)
{
mshi=minter/10;
mge=minter%10;
hshi=hour/10;
hge=hour%10;

dat=d[mge];
q8=1;
delay(2);
q8=0;

dat=d[mshi];
q7=1;
delay(2);
q7=0;

dat=0xbf;
q6=1;
delay(2);
q6=0;

dat=0xbf;
q5=1;
delay(2);
q5=0;

dat=0xbf;
q4=1;
delay(2);
q4=0;

dat=0xbf;
q3=1;
delay(2);
q3=0;

dat=d[hge];
q2=1;
delay(2);
q2=0;

dat=d[hshi];
q1=1;
delay(2);
q1=0;

if(court==20)
{court=0;
      minter++;
      if(minter==99)
         {minter=0;

            hour++;
            if(hour==99)
            hour=0;
            }}}}

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